claudiaw90218 claudiaw90218
  • 16-05-2020
  • Chemistry
contestada

What is the total amount of energy needed to heat 22.6 g of titanium from 1420oC to 1590oC in joules?

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sebassandin
sebassandin sebassandin
  • 22-05-2020

Answer:

[tex]Q=2091J=2.091kJ[/tex]

Explanation:

Hello,

In this case, the formula we use to compute the heat Q by increasing the temperature, in terms of the mass and the heat capacity is:

[tex]Q=mCp(T_2-T_1)[/tex]

Titanium's heat capacity is 0.544284 J/g°C, thus, the for such temperature increase, the heat results positive as shown below:

[tex]Q=22.6g*0.544284\frac{J}{g^oC}*(1590^oC-1420^oC) \\\\Q=2091J=2.091kJ[/tex]

Best regards.

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