tnvu0711
tnvu0711 tnvu0711
  • 17-05-2020
  • Chemistry
contestada

The Ka for benzoic acid is 6.5 × 10−5. Calculate the pH of a 0.12 M benzoic acid solution.

Respuesta :

valeherrera333 valeherrera333
  • 17-05-2020

Answer:

pH=4.05

Explanation:

C7H6O2  -> C7H6O-  + H+

ka= [C7H6O-] [H+]/[C7H6O2]

During equilibrium

[C7H6O-]= [H+]= x^2

[C7H6O2]=0.12-x

Replace

ka= x^2/0.12-x

6.5 x10^-5= x^2/0.12-x

7.8x10^-6 - 6.5 x10^-5x=x^2

x^2+ 6.5 x10^-5x - 7.8x10^-6

Solution of quadratic equation

x=8.8 x10^-5

pH= -log [H+]= -log 8.8 x10^-5=4.05

Answer Link

Otras preguntas

wheels are 1.25 inches in diameter covert the wheels diameter to feet
What is 20% of $40.00 please help
Is 3/4 and 3/8 equivalent fractions and why? Thanks
how to do this equation by elimination 8x +14y= 4 and -6 + -7y =-10
why did the intolerable acts happened??
What are the factors of 65. Like a factor tree.
come si dice come ti chiami in spagnolo???
How was Amsterdam's location an advantage?
wheels are 1.25 inches in diameter covert the wheels diameter to feet
What are the factors of 65. Like a factor tree.