Answer:
The three equivalent options are: [tex]\frac{1}{6}x+47[/tex], [tex]\frac{5}{3}x+35-\frac{3}{2}x+12[/tex], and [tex]5(\frac{1}{3} x+(5)(7)-(3)(\frac{1}{2}x)+(3)(4)[/tex]
Step-by-step explanation:
Expand [tex]5(\frac{1}{3}x+7)-3(\frac{1}{2}x-4)[/tex] to get [tex]\frac{5}{3}x+35-\frac{3}{2}x+12[/tex].
Simplifying this gets you [tex]\frac{1}{6}x+47[/tex].
