bismarkadarkwah80 bismarkadarkwah80
  • 16-06-2020
  • Mathematics
contestada

Find the value of a in the equation below
2sin(1÷4a+20)=√3

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Respuesta :

rumalg123
rumalg123 rumalg123
  • 17-06-2020

Step-by-step explanation:

[tex]sin(1 \div 4a + 20) = \sqrt{3} \div 2 \\ sin(1 \div 4a + 20) =sin 60[/tex]

1÷4a+20=60

1÷4a=4

a=1/160

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