Answer:
132°
Step-by-step explanation:
Given that BA ≅ BC then ∠BAC ≅ ∠BCA
Given that CE bisects ∠BCA, then ∠XCA = 48°/2 = 24°. Similarly, ∠XAC = 48°/2 = 24°
The addition of the angles of a triangle is equal to 180°. Therefore, in triangle XAC:
∠XCA + ∠XAC + ∠CXA = 180°
Replacing with previous results:
24° + 24° + ∠CXA = 180°
∠CXA = 180° - 24° - 24°
∠CXA = 132°
