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Answer: A

Step-by-step explanation:

This problem, may seem abit tricky, but this sequence is all about plugging in.

Since c₁=5, we can solve for c₂ and c₃.

c₂=c₁·2ⁿ⁻¹

c₂=5·2¹

c₂=10

Now that we have c₂, we can find c₃.

c₃=c₂·2ⁿ⁻¹

c₃=10·2²

c₃=40

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