Answer: [tex]5n^2-48n-20=0[/tex]
Step-by-step explanation:
Here are the steps:
[tex]\frac{n+2}{n-2}- \frac{n-2}{n+2} =\frac{5}{6} \\\frac{(n+2)^2-(n-2)^2}{(n+2)(n-2)} =\frac{5}{6} \\\frac{n^2+4n+4-(n^2-4n+4)}{n^2-4} =\frac{5}{6}\\ \frac{n^2+4n+4-n^2+4n-4}{n^2-4} =\frac{5}{6}\\\frac{8n}{n^2-4} =\frac{5}{6}\\48n=5(n^2-4)\\5n^2-20-48n=0\\5n^2-48n-20=0[/tex]
