Answer:
n>[tex]\frac{-6p+12}{63k}[/tex]
Step-by-step explanation:
21k3n>3p-9p+12
21k3n>-6p+12
3n>[tex]\frac{-6p+12}{21k}[/tex]
n>[tex]\frac{-6p+12}{63k}[/tex]
Are you sure you typed the question correctly? like is there supposed to be something between the 21k and the 3n?
