Answer:
- [tex]\frac{1}{2}[/tex]
Step-by-step explanation:
Given
[tex]\frac{x^2y^8}{x^7y^6}[/tex]
= [tex]\frac{y^{(8-6)} }{x^{(7-2)} }[/tex]
= [tex]\frac{y^2}{x^5}[/tex] , substitute values
= [tex]\frac{4^2}{(-2)^{5} }[/tex]
= [tex]\frac{16}{-32}[/tex]
= - [tex]\frac{1}{2}[/tex]
