rabigail557 rabigail557

19-07-2020
Chemistry

contestada

What is the temperature of 0.420 mol of gas at a pressure of 1.5 atm and a volume of 11.2 L?

Respuesta :

nobleswift nobleswift

22-07-2020

Answer:

R = 0.08206L atm mol-1K-1

pv = nRT
1.5 x 11.2 = 0.420 x0.08206 xT
16.8 = 0.0345 xT
T =16.8/0.0345
T = 486.96K
T = 213°C

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