LegolasFox
LegolasFox LegolasFox
  • 19-07-2020
  • Mathematics
contestada

Suppose that a varies inversely with b^2. If a=9 when b=2, find the value of a when b=3.

Respuesta :

rococo908
rococo908 rococo908
  • 19-07-2020

Answer:

a = 4

Step-by-step explanation:

We can set up an equation to model this:

a = [tex]\frac{k}{b^2}[/tex]

Now, we can plug in the information given to find the value of k:

9 = [tex]\frac{k}{2^2}[/tex]

9 = [tex]\frac{k}{4}[/tex]

36 = k

Now, we can find the value of a when b = 3.

a = [tex]\frac{36}{3^2}[/tex]

a = [tex]\frac{36}{9}[/tex]

a = 4

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