Answer:
Step-by-step explanation:
cd(x) would equal c(x) multiplied by d(x) so we get [tex]\frac{5(x+3)}{x-2}\\[/tex] = [tex]\frac{5x+15}{x-2}\\[/tex].
The domain of [tex]\frac{5x+15}{x-2}[/tex] is anything except 2, so the domain of (cd)(x) is (-inf, 2) U (2, inf).
