Answer:
Step-by-step explanation:
Let the consecutive even numbers be 2n , (2n + 2) , (2n +4), (2n + 6)
2n + 2n+2 + 2n+4 + 2n+6 = 180
Add like terms
2n + 2n + 2n + 2n + 2 + 4 + 6 = 180
8n + 12 = 180
Subtract 12 from both sides
8n + 12 - 12 = 180 - 12
8n = 168
Divide both sides by 8
8n/8 = 168/8
n = 21
2n = 2*21 = 42
2n + 2= 2*21 +2 = 42 +2 = 44
2n +4 = 2*21 + 4 = 42 + 4 = 46
2n +6 = 2*21 + 6 = 42 + 6 = 48
The 4 consecutive even integers: 42, 44 , 46 , 48
