Answer:
Step-by-step explanation:
finding the first term by putting n=1
t(1)=4.[tex](1)^{2}[/tex] +2 = 4.1 +2 = 4+2 = 6
finding the second term by putting n=2
t(2)=4.[tex](2)^{2}[/tex] +2 = 4.4 +2 = 16+2 = 18
finding the third term by putting n=3
t(3)=4.[tex](3)^{2}[/tex] +2 = 4.9 +2 = 36+2 = 38
hence first three terms are:
6,18,38,......,4[tex]n^{2}[/tex] +2
