Answer:
x=0
Step-by-step explanation:
in the quadratic formula to only have one solution
[tex]b^{2} -4ac=0[/tex] for [tex]ax^2+bx+c=0[/tex]
so we have
[tex]ax^2+b=c[/tex]
[tex]ax^2+(b-c)=0[/tex]
if we insert in the formula we have
[tex]0^2-4(a)(b-c)=0\\\\-4ab+4ac=0\\\\4ac=4ab\\\\\frac{4ac}{4a} = \frac{4ab}{4a}\\\\c=b[/tex]
[tex]ax^2+b=c\\\\ax^2=b-b\\\\ax^2=0[/tex] since a≠0
[tex]\frac{ax^2}{a}=\frac{0}{a} \\\\x^2=0\\\\x=0[/tex]
