nabinsah360 nabinsah360
  • 20-08-2020
  • Mathematics
contestada

1+tanA.tan2A = sec2A​

Respuesta :

Zuhaibmusht
Zuhaibmusht Zuhaibmusht
  • 20-08-2020

Answer:

Step-by-step explanation:

  1+tan2A(tanA)=sec2A  

Right hand side  

sec2A=1cos2A=1cos2A−sin2A  

=cos2A+sin2Acos2A−sin2A  

=1+tan2A1−tan2A  

=1−tan2A+2tan2A1−tan2A  

=1−tan2A1−tan2A+2tan2A1−tan2A  

=1+2tanA1−tan2A×tanA  

=1+tan2A×tanA  

=Left hand side  

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