Answer:
Option B. pentan-1-ol
Explanation:
We'll begin by writing the name of the compound.
The name of the compound above is pentylpropanoate.
From the name of the compound and the structure, we can suggest the following equation:
CH3CH2COOH + HOCH2CH2CH2CH2CH3 —> CH3CH2COOCH2CH2CH2CH2CH3 + H2O
Thus,
Propanoic acid + pentan-1-ol —> pentylpropanoate + water.
Therefore, the alcohol used in the reaction is pentan-1-ol
