Answer:
We know that in Quadrant 1, both sin x and cos x are positive
We are given:
cosec x = √6 / 2
Since Sin x is 1/ cosec x:
Sinx = 1/cosecx
Sinx = 1/(√6 / 2)
Sinx = 2 /√6
From the pythagoras theorem,
Sin²x + cos²x = 1
Replacing the value of SinΘ
(2 / √6)² + cos²x = 1
4 / 6 + cos²x = 1
cos²x = 1 - (4 / 6)
cos²x = 2 / 6
cosx = √(2 /6)
