1. Factor the first equation.
7x³−11x²−14x+16
7x³−14x²+3x²−6x−8x+16
7x²(x-2)+3x(x-2)-8(x-2)
(x-2)(7x²+3x-8)
2. So this is as far as we have to go because as we can see x-2 is a factor of the equation.
3. Factor the second equation.
7x⁴+22x³+2x²+11
4. As we can see this equation isn’t factorable, so which means that this equation can’t have an exact root so which means x+3 is not a factor for the second equation.
Final answer:
1. B
2.A
