Answer:
p > -3
Step-by-step explanation:
This is an alternating p-series. It is absolutely convergent if│an│converges. 1 / nᵖ⁺³ converges if the exponent is greater than 1.
p + 3 > 1
p > -2
The series is conditionally convergent if │an│diverges. 1 / nᵖ⁺³ diverges if the exponent is greater than 0 and less than or equal to 1.
0 < p + 3 ≤ 1
-3 < p ≤ -2
Combining these two, we get p > -3.
