Answer:
y(y+1)(y-3)=-18
Step-by-step explanation:
[tex]y(2y+3)=y^3+18\\2y^2+3y=y^3+18\\-18=y^3-2y^2-3y\\-18=y(y^2-2y-3)\\-18=y(y^2-3y+y-3)\\-18=y(y(y-3)+(y-3))\\-18=y(y+1)(y-3)\\y(y+1)(y-3)=-18\\[/tex]
