popcorn0610 popcorn0610
  • 20-11-2020
  • Mathematics
contestada

A quadratic equation is shown below.
6x^2 = 10x - 1
What are the solutions to the quadratic equation?

Respuesta :

gardnerdanj gardnerdanj
  • 21-11-2020

Answer:

Two roots are:

[tex]x = \frac{ 5 + \sqrt{19}}{6}\\x = \frac{ 5 - \sqrt{19}}{6}[/tex]

Step-by-step explanation:

[tex]6x^2 = 10x - 1\\6x^2 - 10x + 1 = 0\\\\x = \frac{ 10 + \sqrt{10^2-4*6}}{2*6}\\x = \frac{ 10 + \sqrt{76}}{12}\\x = \frac{ 5 + \sqrt{19}}{6}\\x = \frac{ 5 - \sqrt{19}}{6}[/tex]

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