Respuesta :

apologiabiology
√(ab)=(√a)(√b)
we can split it up
[tex] \sqrt{160a^5b^{15}c^2} =( \sqrt{160})( \sqrt{a^5})( \sqrt{b^{15}})( \sqrt{c^2}) [/tex]=[tex](4 \sqrt{10})( a^2\sqrt{a})( b^7\sqrt{b})(c)=4a^2b^7c \sqrt{10ab} [/tex]