Given:
The given function is
[tex]y=\sec x[/tex]
To find:
The period of given function.
Solution:
General sec function is defined as
[tex]y=A\sec (Bx+C)+D[/tex]
Where, A is amplitude, [tex]\dfrac{2\pi}{B}[/tex] is period, [tex]-\dfrac{C}{B}[/tex] is phase shift and D is vertical shift.
We have,
[tex]y=\sec x[/tex]
Here, B=1. So,
[tex]Period=\dfrac{2\pi}{1}[/tex]
[tex]Period=2\pi[/tex]
Therefore, the period of given function is 2π.
