Answer:
Step-by-step explanation:
[tex]x^{2} + 2x =6\\\\x^{2} +2x + 1^{2} = 6 + 1^{2} \\\\(x+1)^{2} = (\sqrt{7})^{2}[/tex]
[tex]x+1 = \sqrt{7}[/tex]
x = -1 ± [tex]\sqrt{7}[/tex]
