19-01-2021
Mathematics

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Help math problem help

Help math problem help class=

Respuesta :

jimrgrant1 jimrgrant1

19-01-2021

Answer:

[tex]\frac{4}{5}[/tex]

Step-by-step explanation:

sinA = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{16}{20}[/tex] = [tex]\frac{4}{5}[/tex]

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