Answer:
he has 10 type of each coin
Step-by-step explanation:
Total number of cents in possession is calculated as;
= 25 + 10 + 5
= 40 cent
Total amount in possession = $4
= 400 cent
Since he has equal number of each cent, let this equal number be "y";
40cent (y) = 400cent
40y = 400
divide both sides by 40
[tex]\frac{40y}{40} = \frac{400}{40} \\\\y = 10[/tex]
Therefore, he has 10 type of each coin
