Recall that [tex]a^{-b}=\frac{1}{a^b}[/tex]. Therefore, any number [tex]n[/tex] raised to the power of [tex]-1[/tex] will be [tex]\frac{1}{n^1}=\frac{1}{n}[/tex] (the reciprocal of that number).
Thus, the value of the expression [tex]\left (\frac{1}{6}\right)^{-1}[/tex] is:
