Respuesta :

Space

Answer:

2100 g Fe₂(SO₄)₃

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Stoichiometry

  • Using Dimensional Analysis

Atomic Structure

  • Reading a Periodic Table

Explanation:

Step 1: Define

5.26 mol Fe₂(SO₄)₃

Step 2: Identify Conversions

Molar Mass of Fe - 55.85 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Fe₂(SO₄)₃ - 2(55.85) + 3(32.07) + 12(16.00) = 399.91 g/mol

Step 3: Convert

  1. Set up:                               [tex]\displaystyle 5.26 \ mol \ Fe_2(SO_4)_3(\frac{399.91 \ g \ Fe_2(SO_4)_3}{1 \ mol \ Fe_2(SO_4)_3})[/tex]
  2. Multiply/Divide:                 [tex]\displaystyle 2103.53 \ g \ Fe_2(SO_4)_3[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

2103.53 g Fe₂(SO₄)₃ ≈ 2100 g Fe₂(SO₄)₃

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