y=mx+b where m is the slope and b is the y intercept
y=-9x+5 so the slope is -9 for lines to be perpendicular
m1(m2)=-1 so the line q will have a slope -9m=-1, m=1/9 so
q=x/9+b, using point (-9,2) we can solve for b
2=-9/9+b
2=-1+b
b=3 so
q=x/9+3, or more neatly
q=(x+27)/9
