Answer:
[tex]20.61\times 10^{5}Nm^{-2}[/tex]
Explanation:
We are given that
h=20 cm=0.20m
1m=100 cm
Density of water=[tex]\rho=1.0\times 10^3 kg/m^3[/tex]
We have to find the pressure experienced by driver at that depth.
Atmospheric pressure, P0=101 kPa
Pressure experience by driver
[tex]P=\rho hg+P_0[/tex]
Where [tex]g=9.8[/tex]
[tex]P=1.0\times 10^3\times 0.20\times 9.8+101[/tex]
[tex]P=2061KPa[/tex]
1 KPa=[tex]1000Nm^{-2}[/tex]
[tex]P=2061\times 1000=2061000N/m^2[/tex]
[tex]P=20.61\times 10^{5}Nm^{-2}[/tex]
