Answer:
Step-by-step explanation:
You want to factor out perfect squares if they exist.
[tex]1.\ \sqrt{36}=\sqrt{6^2}=6\\ \\ 2.\ \sqrt{40}=\sqrt{2^2(10)}=2\sqrt{10}\\ \\ 3.\ \sqrt{75}=\sqrt{3(5^2)}=5\sqrt{3}\\ \\ 4.\ \sqrt{120}=\sqrt{2^2(30)}=2\sqrt{30}\\ \\ 5.\ \sqrt{84}=\sqrt{2^2(21)}=2\sqrt{21}\\ \\ 6.\ \sqrt{48}=\sqrt{4^2(3)}=4\sqrt{3}[/tex]
