Answer:
[tex] 48\pi \: {m}^{3} [/tex]
Step-by-step explanation:
Radius of the cone (r) = XY = 4 m
Height of the cone (h) = WZ = 9 m
[tex]V_{cone} = \frac{1}{3} \pi {r}^{2}h \\ \\ = \frac{1}{ \cancel3} \pi {(4)}^{2}( \cancel9) \: \: \red{ \bold 3 }\\ \\= \pi \times 16 \times 3 \\ \\\purple {\bold {V_{cone} = 48\pi \: {m}^{3}}} [/tex]
