Answer:
2x(2x - 3)
Step-by-step explanation:
Given:
(3x^2+2y^2-3x)+(2x^2+y^2-2x)-(x^2+3y^2+x)
Written as:
(3x² + 2y² - 3x) + (2x² + y² - 2x) - (x² + 3y² + x)
= 3x² + 2y² - 3x + 2x² + y² - 2x - x² - 3y² - x
Collect like terms
= 3x² + 2x² - x² + 2y² + y²- 3y² - 3x - 2x - x
= 4x² + 0 - 6x
= 4x² - 6x
= 2x(2x - 3)
