Answer:
Step-by-step explanation:
(x⁴+ax²+b) ÷ (x+1) = x³-x²+(a+1)x-(a+1) remainder b+(a+1)
Since x+1 is a factor, b+(a+1) = 0.
(x³-x²+(a+1)x-(a+1)) ÷ (x+2) = x²-3x+(a+7) remainder -3a-15
Since x+2 is a factor, -3a-15 = 0
a = -5
b = 4
x⁴+ax²+b = x⁴ - 5x² + 4 = (x²-4)(x²-1) = (x+2)(x-2)(x+1)(x-1)
