Answer:
A= 131 degrees 3 min or
A = 311 deg 3 min
Step-by-step explanation:
Given is a value -1.14826
We have to find the angle such that
tan A= -1.14826
We know that tangent is negative in II and IV quadrant.
Hence angle A should lie in II or IV quadrant.
First find B such that
tan B =1.14826(removing negative sign)
[tex]B=48.95 =48 degree 57 min[/tex]
Hence [tex]A =180-B : A=360-BA=131.05 : A=311.05\\[/tex]
