Respuesta :

syed514
subtract k ey/n=t-k multiply by n ey=n(t-k) divide by e y=n(t−k)e
HomertheGenius
[tex] \frac{ey}{n}+k = t \\ \frac{ey}{n}=t-k \\ ey=n(t-k) \\ y = \frac{n(t-k)}{e} [/tex]
Thank you.

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