Answer:
(2x+3)(x + 1)
Step-by-step explanation:\
Since the first term has a coefficient, multiply 3 by 2 which results in 6.
Now to break the equation into groups, we have to find two integers that have a product of 6 and a sum of 5. The two integers are 2 and 3.
2x² + 5x + 3
= (2x² + 2x) + (3x + 3)
Factor out the GCF.
2x (x + 1) + 3(x + 1)
Divide the whole equation by x+1.
Now you're left with (x + 1) and (2x+3)
