Answer:
[tex] x = 4 \sqrt{3} [/tex]
Step-by-step explanation:
By geometric mean theorem and Pythagoras theorem:
[tex] {x}^{2} = { (\sqrt{8 \times 4} )}^{2} + {4}^{2} \\ \\ {x}^{2} = { (\sqrt{32} )}^{2} + {4}^{2} \\ \\ {x}^{2} = 32 + 16 \\ \\ {x}^{2} = 48 \\ \\ x = \sqrt{48} \\ \\ x = 4 \sqrt{3} [/tex]
