Answer:
[tex]x=1\pm i[/tex]
Step-by-step explanation:
The given equation is :
[tex]x^2-2x=-2\\\\x^2-2x+2=0[/tex]
The above equation is a quadratic equation whose solution can be given by :
[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]
Here,
a = 1, b = -2 and c = 2
So,
[tex]x=\dfrac{-(-2)\pm \sqrt{(-2)^2-4(1)(2)} }{2(1)}[/tex]
So,
[tex]x=1+i,1-i\\\\x=1\pm i[/tex]
So, the solution of the equation is [tex]1\pm i[/tex].
