Answer:
Hi! The answer to your question is H. [tex]4\sqrt{5}[/tex]
Step-by-step explanation:
[tex]Y1 = 6[/tex]
[tex]Y2 = -2[/tex]
[tex]X1 = 4[/tex]
[tex]X2 = 8[/tex]
[tex]AB = \sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]
[tex]AB = \sqrt{(8-4)^2+(-2-6)^2}[/tex]
[tex]AB =\sqrt{(4)^2+(-8)^2}[/tex]
[tex]AB = \sqrt{16+64}[/tex]
[tex]AB = 4\sqrt{5}[/tex]
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