Answer:
Step-by-step explanation:
The axis AB is passing through the center O as it hold the diameter.
OC⊥AC as tangent is perpendicular to radius.
∠BOC is the central angle and is of same measure as intercepted arc BC:
∠BOC is exterior angle to ΔAOC, hence is equal to sum of non-adjacent interior angles:
- m∠BOC = m∠OAC + m∠OCA
- 102° = m∠1 + 90°
- m∠1 = 102° - 90°
- m∠1 = 12°
