Answer:
Step-by-step explanation:
Given:
[tex]\frac{AD}{DC}=\frac{BE}{EC}[/tex]
To Prove:
AB║DE
Solution:
Since, corresponding sides of ΔACB and ΔDCE are proportional,
[tex]\frac{AD}{DC}=\frac{BE}{EC}[/tex]
Both the triangles will be similar.
ΔACB ~ ΔDCE [By SAS property of similarity]
Therefore, ∠1 ≅ 2 [CPCTC]
Since, ∠1 and ∠2 are the corresponding angles
Therefore, AB║DE [Converse of corresponding angles theorem]
