Answer:
V = 0.104 m³
Explanation:
Given that,
Number of moles, n = 7.70 moles
Pressure, P = 202.6 kPa
Temperature, T = 59.0°C = 332 K
We need to find the volume of the container that the gas. We know that the ideal gas law is as follows :
[tex]PV=nRT\\\\V=\dfrac{nRT}{P}[/tex], R =8.314 m³-Pa/K-mol
Put all the values,
[tex]V=\dfrac{7.7\times 8.314\times 332}{202.6 \times 10^3}\\\\V=0.104\ m^3[/tex]
So, the volume of the container is equal to 0.104 m³.
