Respuesta :

Let the three consecutive integers be x, x+1 and x+2.

According to the question, x+x+1+x+2=51

=>3x+3=51

=>3x+3-3=51-3

=>3x=48

=>x=16

Hence, first integer = 16,

second integer = 16 + 1 = 17 and

third integer = 16 + 2 = 18.

Otras preguntas