Answer:
x = [tex]\sqrt{14}[/tex]
Step-by-step explanation:
Using Pythagoras' identity in both tight triangles.
First in the small triangle to find the third side ( hypotenuse ) h
h² = 1² + 1² = 1 + 1 = 2 ( take square root of both sides )
h = [tex]\sqrt{2}[/tex]
Now use the identity in the larger right triangle
x² + h² = 4²
x² + ([tex]\sqrt{2}[/tex] )² = 16
x² + 2 = 16 ( subtract 2 from both sides )
x² = 14 ( take square root of both sides )
x = [tex]\sqrt{14}[/tex]
