Answer:
3rd option
Step-by-step explanation:
Given
[tex]\frac{x^2-10x+21}{x^2+x-12}[/tex] ← factor numerator and denominator
= [tex]\frac{(x-7)(x-3)}{(x+4)(x-3)}[/tex] ← cancel (x - 3) on numerator / denominator
= [tex]\frac{x-7}{x+4}[/tex]
c is the correct answer of this question.
