9514 1404 393
Answer:
-x +2
Step-by-step explanation:
The expression can be simplified as follows.
[tex]\sqrt{x^2-4x+4}=\sqrt{(x-2)^2}=|x-2|[/tex]
For negative values of its argument, the absolute value changes the sign.
For x < 1, x-2 is negative, so the simplified form is ...
-(x -2) . . . . . for x < 1
-x +2 . . . . . for x < 1
