Answer:
[tex]x=2\sqrt3\ km[/tex]
Step-by-step explanation:
Given that,
The base of a triangle = 2 km
The perpendicular height of the triangle = [tex]2\sqrt{2} \ km[/tex]
We need to find the value of x. It is the Hypotenuse of the triangle. It can be solved as :
[tex]x=\sqrt{(2\sqrt{2})^2+2^2 } \\\\=2\sqrt{2+1 } \\\\=2\sqrt3\ km[/tex]
So, the value of x is equal to [tex]2\sqrt3\ km[/tex].
