Answer:
5x+4y-18=0.
Explanation:
1. the common view of the formula is:
[tex]\frac{x-x_1}{x_2-x_1} =\frac{y-y_1}{y_2-y_1};[/tex]
2. according to the formula above the required equation is:
[tex]\frac{x-2}{-2-2} =\frac{y-2}{5-2}; \ <=> \ 5x+4y-18=0.[/tex]
